Consider this model: xi = axi − 1 + ei, i = 1, …, 3 and x0 = e0. All terms e0, …, e3 are independent and N(0, v2) distributed. Let e = (e0, …, e3) and x = (x0, …x3). Hence e ∼ N(0, v2I). Isolating error terms gives e = tex(e) = tex(L1)tex(x) = L1x
Since Var(e) = v2I we have Var(e) = v2I = LVar(x)L′ so the covariance matrix of x is V1 = Var(x) = v2L−(L−)′ while the concentration matrix (the inverse covariances matrix) is K = v−2L′L.
Augment the AR(1) process above with yi = bxi + ui for i = 1, 2, 3. Suppose ui ∼ N(0, w2) and all ui are independent and inpendent of e. Then (e, u) can be expressed in terms of (x, y) as (e, u) = tex(eu) = tex(L2)tex(xy) = L2(x, y) where